(x+5)(x^2-2x-4)=0

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Solution for (x+5)(x^2-2x-4)=0 equation: 


Simplifying
(x + 5)(x2 + -2x + -4) = 0

Reorder the terms:
(5 + x)(x2 + -2x + -4) = 0

Reorder the terms:
(5 + x)(-4 + -2x + x2) = 0

Multiply (5 + x) * (-4 + -2x + x2)
(5(-4 + -2x + x2) + x(-4 + -2x + x2)) = 0
((-4 * 5 + -2x * 5 + x2 * 5) + x(-4 + -2x + x2)) = 0
((-20 + -10x + 5x2) + x(-4 + -2x + x2)) = 0
(-20 + -10x + 5x2 + (-4 * x + -2x * x + x2 * x)) = 0
(-20 + -10x + 5x2 + (-4x + -2x2 + x3)) = 0

Reorder the terms:
(-20 + -10x + -4x + 5x2 + -2x2 + x3) = 0

Combine like terms: -10x + -4x = -14x
(-20 + -14x + 5x2 + -2x2 + x3) = 0

Combine like terms: 5x2 + -2x2 = 3x2
(-20 + -14x + 3x2 + x3) = 0

Solving
-20 + -14x + 3x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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